And we are done reductionīecause we have reduced the circuit to a single resistor. And keep the rest of the circuit as it is, so let's do that. Replace these two resistors with a single resistor of 10 ohms.
HW TO USE MACSPICE TO CALCULATE CURRENT PLUS
Just the sum of these two, eight plus two, so that will be 10 ohms. Series, the equivalent resistance is just the sum of the And notice all the current will flow here.
HW TO USE MACSPICE TO CALCULATE CURRENT SERIES
They are in series or not? How do we confirm? They need to have the sameĬurrent flowing through them. And now, these two resistorsĪre in series with each other. Of the circuit as it is, but replace this combination with a single resistor of eight ohms. So what we'll do is I'll keep the rest of the circuit as it is. Everything in the circuitĬircuit and the voltage, everything will remain the same. Is that these two resistors connected in parallel can be replaced by a single resistor of eight ohm. Let's write that down, the reciprocal of this. This will be one plus,Īfter multiply this by four to get 40, so multiply the Is going to be one over R1, which is going to be one over 44S, one over R1, plus one over R2, which is going to be one over 10. In resistance in parallel is one over R equivalent Resistance in parallel? Well the formula for equal But anyways, these are in parallel and so we can go aheadĪnd replace this resistor with an equivalent resistance. Was a resistor over here, then these two voltages, these two points won't have the same voltage and then they wouldn't be in parallel. And so notice that this voltage, the potential difference here is the same as potential difference here. Wire across any two points in a wire, so the voltage is the same. The potential difference is always zero within a We're assuming the wiresĭon't have any resistances. Voltage as this point because there are no resistors in between. Resistors are in parallel? They need to have the But if you look at these two resistors, they are in parallel. So they are not in series with each other. And as a result, the current here and here may not be the same. Because of that, someĬurrent might flow up and the rest of theĬurrent will flow here. Now, as the current goesįorward, notice there's a branch. So, I would imagine a smallĬurrent flowing over here and see if that entire current flows here. Need to have the same current flowing through them. Two resistors are in series or not, is remember that they Series, but are they in series? The answer is no. Do you think they are in series? They look like they're in Is identify resistors in series and in parallel. It'll be a great idea to first pause and see if Reduce circuits like this in a previous video, so That, then I can go ahead and apply Ohm's law and calculate it. I need to replace these three resistors with one single resistor. I need to first, calculate what is the equivalent Is since I know the voltage across these two points, So, what's the correct way to do this?, The correct way to do this,
Is the potential difference across each resistor If you substitute V asĥ0 for each resistor, we are implying that 50 volts And that's why I can'tĭirectly solve the problem. I don't know the potentialĭifference across ten ohms. I don't know the potentialĭifference across two ohms. Potential difference across this and this point. Same voltage as this point which means, I know the Voltage as this point and this point as the Is the potential difference across these two points. The potential difference across two ohms, 50 volts The potential difference across two ohms. This for two ohm resistor, then I need to know what's The potential difference across that resistor. Why is that wrong? That's because when we apply Ohm's law, V, which is the voltage, is We now know current through each resistor. I would put V is 50, that's already given, R is 40. To calculate the current here, I would substitute R as two, V And what I'm thinking over here or what I used to think over here is I already know the voltage is 50. So remember Ohm's law? Ohm's law says V equals I times R. What I would do is apply Ohm's law to each resistor directly. Now before we start solving this, let's quickly go through a common mistake that I would do while Written down to save space is to find the voltageĪcross each resistor and to find the current Resistors connected as shown across a 50-volt supply.
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